passing -rx flag in system call in processing

[Scott Smith]

I have had this issue and I would suggest using \" to enclose the variable
as a space will create issues with your system call.

XX="/u/appl/fp/dreport filename -f create -rx\"" {zf{"\" -u -a -v
createselect"

Just a suggestion.

Scott Smith 

-----Original Message-----
From: Filepro-list
[mailto:filepro-list-bounces+scott.filepro=aanet.com.au at lists.celestial.com]
On Behalf Of Walter Vaughan Jr via Filepro-list
Sent: Tuesday, 13 February 2018 5:45 AM
To: filepro-list at lists.celestial.com
Subject: RE: passing -rx flag in system call in processing

You need to have filePro expand the "zf" variable.
 Turn the command you want into a varable as in 

XX="/u/appl/fp/dreport filename -f create -rx" <zf<"-u -a -v createselect"

system xx



-----Original Message-----
From: Filepro-list
[mailto:filepro-list-bounces+wvaughan=steelerubber.com at lists.celestial.com]
On Behalf Of scooter6--- via Filepro-list
Sent: Monday, February 12, 2018 2:40 PM
To: filePro Mailing List <filepro-list at lists.celestial.com>
Subject: passing -rx flag in system call in processing

I'm trying to execute the following within processing but doesn't seem to
work...


@done
system "/u/appl/fp/dreport filename -f create -rx zf -u -a -v createselect

where 'zf' is a variable I have defined in my processing....

this doesn't do anything.....I have verified with a msgbox the value of zf
is correct before it attempts to execute the above....

but if I run from the command line

/u/appl/fp/dreport filename -f create -rx "value of zf" -u -a -v
createselect it runs just fine....

Is it possible I can't run this because the processing is an output
processing table of  filename ?
(i.e. the same file I'm trying to run the system command is the same file
where the output processing resides)

thanks

Scott
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