Getting Initiator's UserID for an External -v table process

[Stanley - stanlyn.com]

Hi,

A new issue...

How do I get the name of the currently logged in user that initiated a
external report.  The report is run like this...

1. user is in clerk and presses "G" which triggers an @KeyG routine that
asks the user for a GL Code and Year. 

2. the process then lookups an "InTheMiddle" table to see it contains a
record matching the current user id and report name.  If found, it updates
the year and gl_id fields to what the user selected.  At this point the user
id is "root" and is represented everywhere correctly.  If not found it
creates one with assignments: lookup(1)=@id ; lookup(2)="2016" ;
lookup(3)="1234-456" ; lookup(4)="MyReport" 

3. Next we do a system call: 
system "/appl/fp/dreport sdgl_detail -f GlDetail -A -u -v gldetail _select
-h 'Printing GL Detail Report'"

4. The -v selection table has code in its init that lookups the
"InTheMiddle" data file and searches for a record where lookup(1)=@id and
lookup(4)="MyReport".  If found it also grabe the gl code and year.  The
issue is here.  The value of lookup(1) record in "InTheMiddle" data file is
root and is correct, however the @id that ran the system call is "filepro"
and therefore never matches anything.

5. I could always use record 1, or an export/import, but that limits me to
single user as the code in the lookup table would always be pointing to the
same place.  The -v table process should never know anything about the user
and must be able to find it based on the id that started the process.

What would be ideal would be to pass a parameter to/with the system call
such as:
 system "/appl/fp/dreport sdgl_detail -f GlDetail -A -u -v gldetail _select
-h 'Printing GL Detail Report' with @id"

Notice the "with @id" at the end as the parameter.  I know this is illegal
in filepro, just need to be able to do the same.

Thanks, 
Stanley