mid

[Richard Kreiss]

> -----Original Message-----
> From: Kenneth Brody [mailto:kenbrody at spamcop.net]
> Sent: Friday, December 03, 2010 5:12 PM
> To: rkreiss at gccconsulting.net
> Cc: Filepro-list at lists.celestial.com
> Subject: Re: mid
> 
> On 12/3/2010 4:52 PM, Richard Kreiss wrote:
> > Have a program using the following type of code
> >
> > If:
> > Then: dim who(6);who["6"]="Cancel"
> >
> > This array is then filled in the form NNNN name
> >
> > If:
> > Then: sl(1,.0)=listbox(who)
> > If:
> > Then: 3=mid(who[sl],"1","4");ab=mid(who[sl],"6","30")
> >
> > Why am I getting a syntax error that points to [sl]?
> 
> Perhaps you are running an ancient version of filePro?
> 
> This small test generates no error in 5.6 or 5.0, though it does in 4.8:
> 
>    1  -------   -   -   -   -   -   -   -   -   -   -   -   -   -
>         ◄ If:
>         Then: dim who(6)
>    2  -------   -   -   -   -   -   -   -   -   -   -   -   -   -
>         ◄ If:
>         Then: sl(1,.0) = listbox(who)
>    3  -------   -   -   -   -   -   -   -   -   -   -   -   -   -
>         ◄ If:
>         Then: xx = mid(who[sl],"1","4"); yy = mid(who[sl],"6","30")
> 
> Unless, that is, you have a typo, and have "s1" rather than "sl".
> 
> --
> Kenneth Brody

Problem solved, checked the map.  It appears that I added a field who and never adjusted this program.  When I changed the array to whose(6) and adjusted the program to use this array name, no syntax error.

My question is why the syntax error at who[sl] and not who("6"]="cancel" which is prior to the who[sl].  Only at the point where it needed to resolve which element did the error occur.

Richard