Subtract 3 years (was Re: FW: simple count)

[Kenneth Brody]

Quoting Bruce Easton (Thu, 12 Jun 2008 15:51:57 -0400):
[...]
>   If:  yd eq ""
> Then:  yd(10,mdyy/,g)=@td-"1095"  'poor man's 3 yrs ago date

Of course, if there's a leap year in that time, you'll be off by a day.
Why not subtract 3 years directly?

     yd(10,mdyy/,g) = addmonth(@t4,"-72")

[...]

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