fieldlen question

[Kenneth Brody]

Quoting Don Coleman (Mon, 8 Jan 2007 10:22:01 -0500):

> Attempting to use fieldlen to determine the length of individual fields
> I need to string together and trim by priority.  Clearly I have something
> incorrect because in the example below AB=0.  Could someone point out my
> error so that AB=7 (COLEMAN being 7 characters).
[...]
>        Then: end
>  @ENTSEL
>        Then: AA(10,*)="COLEMAN"
>        Then: AB=fieldlen(-,AA)
>        Then: SHOW "AB="{AB;display
>        Then: end

You don't have a field named "COLEMAN" in the current file, so the
length is returned as zero.  You probably meant:

    AB = fieldlen(-,"AA")
or
    AB = len(AA)

to get the length of field AA.

However, this will still return 10 and not 7, as AA is defined with
a length of 10.  If you want to know then length after removing the
trailing spaces, you'll need to do something like:

    zz = aa { ""
    ab = len(zz)

(Assuming that ZZ is not declared with a length/type.)

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