I understand that using the COMPARE() function can get this job done as a
couple people have suggested. What I *don't* understand is why using the
character string value of "L" does NOT work.
::end:
@keyT:'@keyt::
::aa="aabcdefglabcdefgiiiL":
::b(2,.0)=instr(aa,chr("76")):
::show "@" <b:
gives: 9
Why?
John Esak