Current menu script

[Jeff Harrison]

--- Jeff Harrison <jeffaharrison at yahoo.com> wrote:

> One of my clients has asked me to log all attempted
> access via menu items to all of their files.  So I
> created a file called accesslog and a library
> process
> to post to it that looks like the following:
> 
> @menu:::
> ::lookup acc = accesslog r=free -e:
> ::acc(1)=@id     ' who:
> ::acc(2)=@td     ' date (when):
> ::acc(3)=@tm     ' time (when):
> ::acc(4)=@pm     ' menu path passed in @pm (what):
> ::acc(5)=""      ' ??  name of menu script (what):
> ::write acc:
> fini:::
> ::exit:
> 
> The problem I am running into is on the post to
> acc(5).   I would like to post the name of the menu
> script being run.  I tried testing by running a
> regular shell script that calls the following
> command
> line:
> 
> /appl/fp/dclerk lib -s1 -z logger -r 1E2
> 
> I was hoping that getenv("0") would return the name
> of
> the script, but it doesn't.  It just returns "".
> 
> I also tried @argv("0") and @argv("1") but no luck
> there either.
> 
> Do I need to do a user command?  I guess I need the
> process name of the parent process.  Any help would
> be
> appreciated.  Thanks.
> 

Hmm, I just thought of a way to do this.  I can just
use -r $0 to the command line.  Duh!

Jeff Harrison
jeffaharrison at yahoo.com

Author of JHExport and JHImport.  The easiest and
fastest ways to generate code for filePro exports and
imports.



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