Current menu script

[Jeff Harrison]

One of my clients has asked me to log all attempted
access via menu items to all of their files.  So I
created a file called accesslog and a library process
to post to it that looks like the following:

@menu:::
::lookup acc = accesslog r=free -e:
::acc(1)=@id     ' who:
::acc(2)=@td     ' date (when):
::acc(3)=@tm     ' time (when):
::acc(4)=@pm     ' menu path passed in @pm (what):
::acc(5)=""      ' ??  name of menu script (what):
::write acc:
fini:::
::exit:

The problem I am running into is on the post to
acc(5).   I would like to post the name of the menu
script being run.  I tried testing by running a
regular shell script that calls the following command
line:

/appl/fp/dclerk lib -s1 -z logger -r 1E2

I was hoping that getenv("0") would return the name of
the script, but it doesn't.  It just returns "".

I also tried @argv("0") and @argv("1") but no luck
there either.

Do I need to do a user command?  I guess I need the
process name of the parent process.  Any help would be
appreciated.  Thanks.

Jeff Harrison
jeffaharrison at yahoo.com

Author of JHExport and JHImport.  The easiest and
fastest ways to generate code for filePro exports and
imports.



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